{"id":19,"date":"2020-10-05T15:57:04","date_gmt":"2020-10-05T15:57:04","guid":{"rendered":"https:\/\/maritimesa.org\/nautical-science-grade-11\/?p=19"},"modified":"2021-01-07T08:03:28","modified_gmt":"2021-01-07T08:03:28","slug":"test-post-title","status":"publish","type":"post","link":"https:\/\/maritimesa.org\/nautical-science-grade-11\/2020\/10\/05\/test-post-title\/","title":{"rendered":"Parallel sailing"},"content":{"rendered":"<p>By <strong>parallel sailing<\/strong> we mean travelling along a parallel of latitude from one place to another. This means that one would either be travelling directly westward or eastward [270\u00b0 (T) or 090\u00b0 (T)]. The distance along a parallel of latitude between two particular meridians decreases as the meridians converge towards the poles. The distance decreases as the latitude increases. Because of this, the distance along a chosen latitude is referred to as \u201cDeparture\u201d and it is expressed in nautical miles.<br \/>\nTo determine the distance or departure between two positions, the following formula is used:<\/p>\n<div id=\"attachment_24\" style=\"width: 910px\" class=\"wp-caption alignnone\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-24\" class=\"wp-image-24 size-full\" src=\"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_1.jpg\" alt=\"\" width=\"900\" height=\"312\" srcset=\"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_1.jpg 900w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_1-300x104.jpg 300w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_1-768x266.jpg 768w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_1-260x90.jpg 260w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_1-50x17.jpg 50w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_1-150x52.jpg 150w\" sizes=\"(max-width: 900px) 100vw, 900px\" \/><p id=\"caption-attachment-24\" class=\"wp-caption-text\">See Appendix A below for the derivation of this formula.<\/p><\/div>\n<p>For example: The latitude of the parallel is 40\u00b0 S and the longitudes of the two positions are 15\u00b0 E and 60\u00b0E respectively. Subtracting the one longitude from the other we get a d\u2019long of 45\u00b0 or 2 700\u2019. To calculate the distance along the parallel (departure) we apply the above data to the formula as follows:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-25 size-full\" src=\"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_2.jpg\" alt=\"\" width=\"900\" height=\"219\" srcset=\"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_2.jpg 900w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_2-300x73.jpg 300w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_2-768x187.jpg 768w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_2-260x63.jpg 260w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_2-50x12.jpg 50w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_2-150x37.jpg 150w\" sizes=\"(max-width: 900px) 100vw, 900px\" \/><\/p>\n<p>In help memorize the formula use the following figure:<\/p>\n<div id=\"attachment_26\" style=\"width: 910px\" class=\"wp-caption alignnone\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-26\" class=\"wp-image-26 size-full\" src=\"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_3.jpg\" alt=\"\" width=\"900\" height=\"515\" srcset=\"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_3.jpg 900w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_3-300x172.jpg 300w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_3-768x439.jpg 768w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_3-255x146.jpg 255w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_3-50x29.jpg 50w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.1_fig_3-131x75.jpg 131w\" sizes=\"(max-width: 900px) 100vw, 900px\" \/><p id=\"caption-attachment-26\" class=\"wp-caption-text\">Side CA is the d\u2019long, side CB is the departure and the angle ACB is the latitude.<\/p><\/div>\n<p>As a guide, a pro-forma of the method used is attached below as Appendix B entitled &#8216;Parallel Sailing&#8217;.<\/p>\n<p><strong>Appendix A.<\/strong><br \/>\nDerivation of the parallel sailing formula:<\/p>\n<div id=\"attachment_575\" style=\"width: 910px\" class=\"wp-caption alignnone\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-575\" src=\"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2021\/01\/11.1.1.4_fig_4_r.jpg\" alt=\"\" width=\"900\" height=\"667\" class=\"size-full wp-image-575\" srcset=\"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2021\/01\/11.1.1.4_fig_4_r.jpg 900w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2021\/01\/11.1.1.4_fig_4_r-300x222.jpg 300w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2021\/01\/11.1.1.4_fig_4_r-768x569.jpg 768w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2021\/01\/11.1.1.4_fig_4_r-197x146.jpg 197w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2021\/01\/11.1.1.4_fig_4_r-50x37.jpg 50w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2021\/01\/11.1.1.4_fig_4_r-101x75.jpg 101w\" sizes=\"(max-width: 900px) 100vw, 900px\" \/><p id=\"caption-attachment-575\" class=\"wp-caption-text\">Derivation of the parallel sailing formula.<\/p><\/div>\n<p>The above figure represents the earth where P, P\u2019 represents the two poles, Q, Q\u2019 represents the equator , L, L represents a parallel latitude, C represents the middle of the earth and lastly F that represents the centre of the small circle L, L\u2019.<\/p>\n<p>E and D are two positions on latitude L, L\u2019. PAP\u2019 and PBP\u2019 are meridians passing through positions E and D while CA, CB and CD are radii of the earth. According to circular measure, the length of an arc, which subtends any given angle at its centre, is proportional to the radius. From this, DE\/DF = BA\/AC, where DE is the departure and BA is the d.long. Therefore DE\/BA = DF\/AC and since DC and AC are both radii of the earth, DE\/BA = DF\/DC. It follows therefore that DE\/BA = cosine angle FDC.<br \/>\nThus departure\/d.long = cosine latitude.<\/p>\n<p><strong>Appendix B.<\/strong><br \/>\nPro-forma for parallel sailing.<\/p>\n<div id=\"attachment_34\" style=\"width: 910px\" class=\"wp-caption alignnone\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-34\" class=\"wp-image-34 size-full\" src=\"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.4_fig_1.jpg\" alt=\"\" width=\"900\" height=\"624\" srcset=\"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.4_fig_1.jpg 900w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.4_fig_1-300x208.jpg 300w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.4_fig_1-768x532.jpg 768w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.4_fig_1-211x146.jpg 211w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.4_fig_1-50x35.jpg 50w, https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-content\/uploads\/sites\/6\/2020\/10\/11.1.1.4_fig_1-108x75.jpg 108w\" sizes=\"(max-width: 900px) 100vw, 900px\" \/><p id=\"caption-attachment-34\" class=\"wp-caption-text\">Pro-forma for parallel sailing.<\/p><\/div>\n","protected":false},"excerpt":{"rendered":"<p>By parallel sailing we mean travelling along a parallel of latitude from one place to another. This means that one would either be travelling directly westward or eastward [270\u00b0 (T) or 090\u00b0 (T)]. The distance along a parallel of latitude between two particular meridians decreases as the meridians converge towards [&hellip;]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[4,5,6],"tags":[],"class_list":["post-19","post","type-post","status-publish","format-standard","hentry","category-11-1-navigation","category-11-1-1-sailings","category-11-1-1-1-parallel-sailing"],"_links":{"self":[{"href":"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-json\/wp\/v2\/posts\/19"}],"collection":[{"href":"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-json\/wp\/v2\/comments?post=19"}],"version-history":[{"count":16,"href":"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-json\/wp\/v2\/posts\/19\/revisions"}],"predecessor-version":[{"id":582,"href":"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-json\/wp\/v2\/posts\/19\/revisions\/582"}],"wp:attachment":[{"href":"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-json\/wp\/v2\/media?parent=19"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-json\/wp\/v2\/categories?post=19"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/maritimesa.org\/nautical-science-grade-11\/wp-json\/wp\/v2\/tags?post=19"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}